An object is placed at a distance of 12 cm from a concave mirror of radius of curvature 16 cm. Find the position of the image.
Answers
Answered by
7
Answer:
-1/24
Explanation:
u =-12
r=16
u=?
f=r/2
f=16/2
1/v+1/u =1/f
1/v+1/-12 =1/8
1/v=1/8 -1/12
1/v =3-2/24 = -1/24
Answered by
0
Explanation:
Answer :-
Image distance is -24 cm.
Explanation :-
Given :-
Object distance (u) = -12 cm
Radius of curvature (r) = -16 cm
To find :-
Position of the image/Image distance (v) = ?
Solution :-
Radius of curvature (r) = -16 cm
Focal length (f) = r/2
-16/2
∴ Focal length is -8 cm.
________________________________
Using mirror formula :
1/v + 1/u = 1/f
1/v + 1/(-12) = 1/(-8)
1/v = 1/-8 - 1/-12
1/v = (1 × -3 - 1 × -2)/24
1/v = -1/24
v = -24
∴ Image distance (v) is -24 cm.
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