Question

An object is placed at a distance of 12 cm from a concave mirror of radius of curvature 16 cm. Find the position of the image​

Answer 1

$<font color=red><marquee behavior=alternate>Solution</marquee></font>$

from the concave mirror formula..

$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$

now ..given

u=-12cm

r=-16cm

now...f=(r/2)=-16/2=-8cm

therefore...

$\frac{1}{v} + \frac{1}{ - 12} = \frac{1}{ - 8} \\ = > \frac{1}{v} = \frac{1}{12} - \frac{1}{8} \\ = > \frac{1}{v} = \frac{2 - 3}{24} \\ = > v = - 24 \: \: cm$

therefore the image will form on the same side where the object is placed at a distance of 24 cm from the mirror..

$<font color=green><marquee direction="down">hope this help you$

Answer 2

Answer:

The distance of 12 cm from radius of curvature 16 cm the answer is -24