Physics, asked by saumyasingh38370, 8 months ago

an object is placed at a distance of 12 cm from a concave mirror its image formed at a distance of 24cm . what will be the magnification​

Answers

Answered by sharbba00002334313
1

Answer:

-2

Explanation:m= -v/u=24/-12=-2

Answered by Anonymous
1

Answer:

f = -8cm

Explanation:

Image is inverted so magnification ratio should be negative.

Since the object size is double so magnification ratio m=−2

now the object distance from mirror  u=−12

So m  = -\frac{v}{u}

-2 = \frac{v}{-12} \\

v= -24cm

Image is formed at 24 cm from mirror in same direction of object.

Now be know

\frac{1}{f} = \frac{1}{v } +\frac{1}{u}

\frac{1}{f} = \frac{1}{-24} +\frac{1}{-12}\\\\f = -8cm

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