Question

an object is placed at a distance of 12 cm from a concave mirror of radius of curvature 16 cm , find the position of the image ?

no spams !​

Answer 1

Answer:

Put f= - 8 cm and u= -12 cm. Therefore, the position of the image is - 24cm.

Answer 2

Step-by-step explanation:

Answer :-

Image distance is -24 cm.

Explanation :-

Given :-

Object distance (u) = -12 cm

Radius of curvature (r) = -16 cm

To find :-

Position of the image/Image distance (v) = ?

Solution :-

Radius of curvature (r) = -16 cm

Focal length (f) = r/2

-16/2

∴ Focal length is -8 cm.

________________________________

Using mirror formula :

1/v + 1/u = 1/f

1/v + 1/(-12) = 1/(-8)

1/v = 1/-8 - 1/-12

1/v = (1 × -3 - 1 × -2)/24

1/v = -1/24

v = -24

∴ Image distance (v) is -24 cm.

Answer 3

Step-by-step explanation:

Answer :-

Image distance is -24 cm.

Explanation :-

Given :-

Object distance (u) = -12 cm

Radius of curvature (r) = -16 cm

To find :-

Position of the image/Image distance (v) = ?

Solution :-

Radius of curvature (r) = -16 cm

Focal length (f) = r/2

-16/2

∴ Focal length is -8 cm.

________________________________

Using mirror formula :

1/v + 1/u = 1/f

1/v + 1/(-12) = 1/(-8)

1/v = 1/-8 - 1/-12

1/v = (1 × -3 - 1 × -2)/24

1/v = -1/24

v = -24

∴ Image distance (v) is -24 cm.

Answer 4

Step-by-step explanation:

Answer :-

Image distance is -24 cm.

Explanation :-

Given :-

Object distance (u) = -12 cm

Radius of curvature (r) = -16 cm

To find :-

Position of the image/Image distance (v) = ?

Solution :-

Radius of curvature (r) = -16 cm

Focal length (f) = r/2

-16/2

∴ Focal length is -8 cm.

________________________________

Using mirror formula :

1/v + 1/u = 1/f

1/v + 1/(-12) = 1/(-8)

1/v = 1/-8 - 1/-12

1/v = (1 × -3 - 1 × -2)/24

1/v = -1/24

v = -24

∴ Image distance (v) is -24 cm.