Question

an object is placed at a distance of 12 cm from a concave mirror of radius of curvature 16 cm.Find the position of the image​

Answer 1

Answer:

Hi friends

Explanation:

The expression for the focal length is as follows;

f=\frac{R}{2}

Here, R is the radius of curvature.

Put R= 8 cm.

f=\frac{16}{2}

f=8 cm

The expression for the mirror's formula is as follows;

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}

Here, u is the object distance, v is the image distance and f is the focal length.

Calculate the position of the image.

\frac{1}{v}=\frac{1}{f}-\frac{1}{u}

Put f= - 8 cm and u= -12 cm.

\frac{1}{v}=\frac{1}{-8}-\frac{1}{-12}

\frac{1}{v}=\frac{-1}{24}

v=-24 cm

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Answer 2

Answer:

-12 is the answer for the question