an object is placed at a distance of 12 cm from a concave mirror the image formed is real and 4 times greater than the object calculate the distance of image formed in front of concave mirror
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use magnification formula of
hi/h○= -V/U
where hi height of image
h○ height of object
V image distance
U object distance
here it is given that U= -12 (-ve because object is real)
hi/ho=4/1
-V/U=4/1
-V/-12=4/1
V=12×4=48
hence V=48 cm
nature of image = Virtual,large in size and erecte
Anonymous:
can't understand
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