Question

An object is placed at a distance of 12 cm from a convex lens of focal length 8 cm. Find :

i) the position of the image

ii) nature of the image​

Answer 1

Answer:

Position: Beyond 2F2 (24cm)

Nature: Real and Inverted

Explanation:

Please find the ATTACHMENT.

Answer 2

QuEstion:—

An object is placed at a distance of 12 cm from a convex lens of focal length 8 cm. Find :

i) the position of the image

ii) nature of the image

AnswEr:—

$\textsf{(i) the postion of the image:}$

•focal length (f)= +12 cm ( convex lens)

•object distance(u)= -8 cm

• image distance (v)= ??

using lens formula

$\longrightarrow \: { \tt{\frac{1}{v} - \frac{1}{u} = \frac{1}{f}}} \\ \\ \\ \longrightarrow \: { \tt{ \frac{1}{v} - \frac{1}{ - 12} = \frac{1}{8} }} \\ \\ \\ \longrightarrow \: { \tt{ \frac{1}{v} + \frac{1}{12} = \frac{1}{8} }} \\ \\ \\ \ \longrightarrow{ \tt{ \frac{1}{v} = \frac{1}{8} - \frac{1}{12} }} \\ \\ \\ \longrightarrow \: { \tt{ \frac{1}{v} = \frac{1}{24} }} \\ \\ \\ \longrightarrow \: \bf{v = 24 \: cm}$

•°• Image distance is 24 cm

magnification :- v/u = 24/-12 = -2

$\textsf{(ii) nature of the image:}$

• The positive sign(+24) indicates that image is on the right side of the lens.

• Image is inverted and real.

• Image is inlarge.