Question

An object is placed at a distance of 12cm in front of concave mirror it forms a real image 4times larger than the object . Calculate the distance of the image?

Answer 1

Answer:

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Answer 2

IMAGE DISTANCE IS -48 cm.

Given:

• Object distance = 12 cm
• Real image is 4 times object

To find:

• Image distance ?

Calculation:

We know that :

• When the image is real, it is inverted. Hence the magnification sign will be negative.

Now, we can say:

$magnification = - \dfrac{v}{u}$

• "v" is image distance and "u" is object distance.

$\implies - 4 = - \dfrac{v}{( - 12)}$

$\implies - 4 = \dfrac{v}{12}$

$\implies v = - 4 \times 12$

$\implies v = - 48 \: cm$

So, image distance is -48 cm.