Question

an object is placed at a distance of 12cm in front of a concave mirror and the image formed behind the mirror at a distance of 48 cm from the mirror.what is the nature of the image ? calculate the focal length of the given mirror.​

Answer 1

Explanation:

v=12cm

u=48cm

f=?

$\frac{1}{v} + \frac{1}{u} = \frac{1}{f} \\ \frac{1}{12} + \frac{1}{48} = \frac{1}{f} \\ = \\ \frac{1}{12} \times 36 + \frac{1}{48} \times 36 = \frac{1}{f} \\ f = \frac{3 + 0.75}{36} \\ f = \frac{3.75}{36} \\ f = 0.1cm$

Answer 2

Answer:

Explanation:

u = -12 cm

v = 48 cm

f = ?

1/v + 1/u = 1/f

1/48 + 1/-12 =1/f

1 - 4/48 = 1/f

-3/48 =1/f

-3f = 48

f =  - 48/3

f = - 16 Ans