An object is placed at a distance of 134 cm from the mirror at a height of 90 cm. the radius of the curvature us (-)30 cm. find the image of the object .also find the type of mirror ised in this eg. state the nature of the image
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Explanation:
ANSWER
(a) In concave mirror, using sign convention
u=−10cm
R=−15cm
f=
2
−15
cm
Using mirror’s relation
v
1
+
u
1
=
f
1
v
1
=
f
1
−
u
1
v
1
=−
15
2
+
10
1
v
1
=
30
−1
v=−30cm
Image is real and it forms at a distance of 30 cm in front of mirror.
Magnification
m=
u
−v
m=
−10
30
=−3
This shows image is inverted and 3 times magnified.
(b) again using sign convention
u=−5cm
f=
2
−15
cm
v
1
=
f
1
−
u
1
v
1
=
15
1
v=+15cm
Image is formed at a distance of 15 cm behind the mirror.
Magnification
m=
u
−v
=
−5
−15
=3
+3 magnification shows image is virtual and erect.
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