An object is placed at a distance of 15 cm from a concave lens of focal length 6 cm find the location nature and size of the image
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question is incomplete either height of image or height of object is required.
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answer : image distance, v = -30/7 ≈ -4.3 cm , size of image is smaller than that of object i.e., 2/7 times of object.
object distance, u = -15cm
Focal length of concave lens, f = -6cm
using lens maker formula, 1/v - 1/u = 1/f
⇒1/v - 1/-15 = 1/-6
⇒1/v + 1/15 = -1/6
⇒1/v = -1/6 - 1/15 = (-5 - 2)/30
⇒v = -30/7 ≈ -4.3 cm
image distance would be 4.3cm left side of the lens.
magnification, m = v/u
= (-30/7)/(-15)
= 2/7
size of image = 2/7 × size of object.
hence, image is smaller than object.
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