an object is placed at a distance of 15 cm from a convex mirror of focal length 30 cm .Find position and nature of image
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By the mirror formula
1/f = 1/v + 1/u
1/30 = 1/v + (-1/15)
1/30 + 1/15 = 1/v
(1 + 2)/30 = 1/v
v = 10cm
nature - virtual and erect image is formed.
1/f = 1/v + 1/u
1/30 = 1/v + (-1/15)
1/30 + 1/15 = 1/v
(1 + 2)/30 = 1/v
v = 10cm
nature - virtual and erect image is formed.
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