an object is placed at a distance of 15 cm from a convex lens the magnification of the image is -2 then the image distance is
a. 50cm
b.-50cm
c.12.5cm
d.-12.5cm
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Given that u=−15cm f=20cm
Given that u=−15cm f=20cm Now by lens formula
Given that u=−15cm f=20cm Now by lens formula f
Given that u=−15cm f=20cm Now by lens formula f1
Given that u=−15cm f=20cm Now by lens formula f1
Given that u=−15cm f=20cm Now by lens formula f1 =
Given that u=−15cm f=20cm Now by lens formula f1 = v
Given that u=−15cm f=20cm Now by lens formula f1 = v1
Given that u=−15cm f=20cm Now by lens formula f1 = v1
Given that u=−15cm f=20cm Now by lens formula f1 = v1 −
Given that u=−15cm f=20cm Now by lens formula f1 = v1 − u
Given that u=−15cm f=20cm Now by lens formula f1 = v1 − u1
Given that u=−15cm f=20cm Now by lens formula f1 = v1 − u1
Given that u=−15cm f=20cm Now by lens formula f1 = v1 − u1
Given that u=−15cm f=20cm Now by lens formula f1 = v1 − u1 v
Given that u=−15cm f=20cm Now by lens formula f1 = v1 − u1 v1
Given that u=−15cm f=20cm Now by lens formula f1 = v1 − u1 v1
Given that u=−15cm f=20cm Now by lens formula f1 = v1 − u1 v1 =
Given that u=−15cm f=20cm Now by lens formula f1 = v1 − u1 v1 = 10
Given that u=−15cm f=20cm Now by lens formula f1 = v1 − u1 v1 = 101
Given that u=−15cm f=20cm Now by lens formula f1 = v1 − u1 v1 = 101
Given that u=−15cm f=20cm Now by lens formula f1 = v1 − u1 v1 = 101 −
Given that u=−15cm f=20cm Now by lens formula f1 = v1 − u1 v1 = 101 − 20
Given that u=−15cm f=20cm Now by lens formula f1 = v1 − u1 v1 = 101 − 201
Given that u=−15cm f=20cm Now by lens formula f1 = v1 − u1 v1 = 101 − 201
Given that u=−15cm f=20cm Now by lens formula f1 = v1 − u1 v1 = 101 − 201
Given that u=−15cm f=20cm Now by lens formula f1 = v1 − u1 v1 = 101 − 201 ⇒v=20cm
Given that u=−15cm f=20cm Now by lens formula f1 = v1 − u1 v1 = 101 − 201 ⇒v=20cmThe image gets formed at 20 cm to the right of the lens and it will be diminished, inverted and real in nature.
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