Question

an object is placed at a distance of 15 cm from a diverging mirror(convex mirror) of focal length 6 cm find the nature and position of object.​

Answer 1

given that

u= -10 cm

f= 15 cm

Find out

We need to find v

Formula

We know the formula

1/f = 1/v + 1/u

Therefore, 1/v= 1/f – 1/u

Substituting the known values in the above equation we get,

1/v= 1/15 + 1/10

1/v = (2+3)/30 (lcm)

Hencev=5/30 = 6 cm

v= 6cm

Nature of the image: The image is formed behind the mirror and it is virtual and erect.

Answer 2

Answer:

The image is placed at $\frac{30}{7} cm$. It is formed behind the mirror and it is virtual and erect.

Explanation:

It is given that $u=-15cm$

$f=6cm$

$v=?$

We will use mirror formula here

$\frac{1}{f} =\frac{1}{v}+\frac{1}{u}$

$\frac{1}{f} -\frac{1}{u}=\frac{1}{v}$

$\frac{1}{6} +\frac{1}{15}=\frac{1}{v}$

$\frac{1}{v}=\frac{7}{30}$

$v=\frac{30}{7}$

Hence, image distance is $\frac{30}{7} cm$ behind the mirror.

The image is virtual and erect.

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