Question

An object is placed at a distance of 15 cm in front of a convex mirror of focal length 12 cm. Find the position of the image ​

Answer 1

$\huge \mathtt{ \fbox{Solution :)}}$

By sign convention ,

Object distance (u) = -15 cm

Focal length (f) = 12 cm

We know that , the formula of mirror is given by

$\large \mathtt{ \fbox{ \frac{1}{v} + \frac{1}{u} = \frac{1}{f} }}$

Thus ,

$\mapsto \sf \frac{1}{v} - \frac{1}{15} = \frac{1}{12} \\ \\ \mapsto \sf \frac{1}{v} = \frac{1}{12} + \frac{1}{15} \\ \\ \mapsto \sf \frac{1}{v} = \frac{15 + 12}{180} \\ \\ \mapsto \sf v = \frac{180}{27} \\ \\ \mapsto \sf v = 6.67 \: \: cm$

Hence , the image distance is 6.67 cm to the right of the mirror

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Answer 2

Answer:

The image will be formed at a distance of 60 cm in front of the mirror.

Explanation:

Referred to the attachment.