Question

An object is placed at a distance of 15 cm in front of a convex mirror of radius of curvature of 10 cm. Find :- (a) position of the image (b) the magnification

Answer 1

Answer:

U=-10cm

R=-15cm

f=-15/2cm

so by

1/v+1/u=1/f

v=-150 /(-20+15)

=-30cm

m=-v/u=-(-30/10)=-3

Explanation:

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Answer 2

Formula = 1/v + 1/u = 1/f

u=-15 cm f=-10 cm. v=?

1/v + (1/-15) = 1/-10

1/v =( -1/15) - (-1/10)

1/v = -1/15 + 1/10

1/v =( -2+3/30)

1/v = 1/30

v= 30 cm

Thus , position of image is 30 cm behind the mirror.

Magnification = h'/h = -v/u = (f-v)/f

=> (-10 -30)/-10

=> -40/-10 = 4 cm and

Explanation: