An object is placed at a distance of 15 cm in front of a convex mirror of radius of curvature of 10 cm. Find :- (a) position of the image (b) the magnification (c) What will be the nature of the image real or virtual ?
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Answered by
5
Answer:
It is to be remembered that a convex mirror always forms the virtual, erect and diminished image.
Given: Object distance, u=−10cm Focal length, f=15cm
To find: Image distance, v
From mirror formula :
v
1
+
u
1
=
f
1
v
1
−
10
1
=
15
1
v
1
=
15
1
+
10
1
=
150
25
v=6cm
Hence image will be formed 6 cm beyond the mirror, i.e virtual magnification
m=
u
−v
=
−10
−6
=0.6
Hence it will be erect and diminished.
Answered by
1
Answer:
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Explanation:
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