An object is placed at a distance of 15cm from a convex mirrior of focal length 30cm. find the position and the nature of the image?
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m= 0.6
so the image is smaller in size , virtual and erect.
so the image is smaller in size , virtual and erect.
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hello friend
u=-15cm
f=30cm
v=?
using mirrors formula
=}1/f =1/v+1/u
=}1/30=1/v-1/15
=}1/30+1/15=1/v
=}3/30=1/v
=}1/10=1/v
=}v=10cm
nature of image = virtual and erect
u=-15cm
f=30cm
v=?
using mirrors formula
=}1/f =1/v+1/u
=}1/30=1/v-1/15
=}1/30+1/15=1/v
=}3/30=1/v
=}1/10=1/v
=}v=10cm
nature of image = virtual and erect
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