An object is placed at a distance of 15cm from convex mirror of focal length 200cm. Find the position and nature of the image.
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Explanation:
Given = object distance, u = -15cm
Focal length, F = 200 cm
To find = position and nature of image
We know that,
1/f = 1/v+1/u
1/200 = 1/v + 1/(-15)
1/200 = 1/v - 1/15
1/200 + 1/15 = 1/v
300 + 40/600 = 1/v
340/600 = 1/v
v = 1.76 cm
The positive sign shows that the image formed will be virtual and erect, and the image will formed behind the mirror.
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