An object is placed at a distance of 15cm from convex mirror of focal length 200cm. Find the position and nature of the image.
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The focal length f = +15 cm,
Object distance u = -10 cm
From mirror formula
1/f = 1/v +1/u
1/v = 1/15 +1/10
1/v = 5/30
v = + 6 cm
The image is formed 6 cm behind the mirror; it is a virtual and erect image
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