an object is placed at a distance of 15cm in front of a convex mirror with a radius of curvature 10cm wherewill the image form what is the nature of image
Answers
Answered by
23
hope this helps u
given :-
- u = -15 cm
- 2f or r = 10cm
- v?
- nature of image ?
solution
2f = 10
f = 10/2
f = 5cm
1/f = 1/v+1/u
1/v= 1/f-1/u
= 1/5 - (-1/15)
= 1/5 + 1/15
= 3+1/15
1/v = 4/15
15/4v = o
v = 15/4
v = 3.75cm
as we know v is positive the image is virtual and erect image
we know that convex can produce only erect image
Answered by
5
Answer:
v (image distance) = 3.75 cm
Explanation:
u = -15 cm; R = 10 cm
Since, R=2 (focal length)
therefore, f = R/2 = 10/2 = 5 cm
now, 1/f = 1/v + 1/u
therefore, 1/v = 1/f - 1/u
therefore, 1/v = 1/5 - 1/(-15)
therefore, 1/v = 1/5 + 1/15
therefore, 1/v = (3 + 1)/15
therefore, 1/v = 4/15
therefore, v = 15/4
therefore, v = 3.75 cm
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