Question

An object is placed at a distance of 16 cm from a mirror of focal length ‘f’ such that an erect and diminished image, 1/4th the size of object is obtained. Find the value of ‘f’.​

Answer 1

Answer:

Given :    u=−0.5 m

Convex mirror forms erect image of real object.

Using,   hohi=−uv

Or   41=−(−0.5)v

⟹ v=0.125 m

Using mirror formula,   v1+u1=f1

∴   0.1251+−0.51=f1

⟹ f=0.16 m

Step-by-step explanation:

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Answer 2

Answer:

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