Physics, asked by Anonymous, 9 months ago

an object is placed at a distance of 16 cm in front of a concave mirror. it from a real image 4 times larger than the object calculate the distance of the image from the mirror. also calculate the focal length of the given mirror (don't post useless answer)​

Answers

Answered by d687cyoyo
6

f, the focal length, is positive for a concave mirror, and negative for a convex mirror. When the image distance is positive, the image is on the same side of the mirror as the object, and it is real and inverted. When the imagedistance is negative, the image is behind themirror, so the image is virtual and upright.

Answered by ItzLuckyCharm
27

Question :-

An object is placed at a distance of 16 cm in front of a concave mirror. it from a real image 4 times larger than the object calculate the distance of the image from the mirror. also calculate the focal length of the given mirror.

Answer :-

 \bf{\underline\red{-64\:cm}}

Solution :-

 \bf{\underline\green{Given\: :}}

Distance of object from concave mirror = 16 cm

Real Image larger than object = 4 times

 \bf{\underline\orange{Calculation-}}

Real Image = - m

M = - 4 ( -4 is because of real image )

We know that -

m =  \frac{ - v}{u}

here : m = -4 , u = 16 , v = ?

 - 4 =  \frac{v}{16}

 - 4 \times ( - 16) = v

v =  - 64 \: cm

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