Question

an object is placed at a distance of 16cm in front of a concave mirror. it forms real image 4 times larger than the object. calculate the distance of the image from the mirrors. also calculate the focal length of the given mirror ​

Answer 1

Answer:

Explanation:

distance of object from mirror (u) =  -16

height of image = 4*height of object

    $hi = - 4 ho\\hi/ho = -4\\m = -4\\-v/u = -4\\v = 4u\\v = 4(-16)\\v = -64 cm\\1/v + 1/u = 1/f\\1/(-64) + 1/(-16) = 1/f\\-1/64 - 1/16 = 1/f\\-1-4/64 = 1/f \\-5/64 = 1/f\\f = -64/5\\f = -12.8 cm$