Question

an object is placed at a distance of 20 cm from a convex mirror of focal length 25 cm calculate the position of the image . discuss its nature

Answer 1

Answer:

u=-20

f=25

1/f=1/u+1/v

1/v=1/25-(-1/20)

1/v=(4+5)/100

1/v=9/100

v=100/9=11.1cm

nature-it is erect diminished and behind the mirror

PLEASE MARK AS BRAINLIEST

Answer 2

Answer:

11 cm = image distance

0.55 cm = magnification

Image is virtual and erect.

Step-by-step explanation:

Convex mirror :

u (object distance) = - 20 cm

f (focal length) = + 25 cm

v (image distance) = ?

Mirror formula :

1/v + 1/u = 1/f

1/v = 1/f - 1/u

1/v = 1/25 - 1/-20

1/v = 9/100

v = 100/9

v = 11 cm

Since v is positive, image is formed behind the mirror, so the image is virtual.

Magnification :

m = -v/u

m = -11/-20

m = 0.55 cm

Since magnification and hence height of the image is positive, image is erect.