Question

an object is placed at a distance of 20 cm, from a convex mirror of 45 cm . find the position and nature of image​

Answer 1

\bf\huge u = -20cm , f = 15cmu=−20cm,f=15cm

\bf\huge\frac{1}{f} = \frac{1}{u}+\frac{1}{v}

f

1

=

u

1

+

v

1

\bf\huge\frac{1}{v} = \frac{1}{15} - \frac{1}{-20}

v

1

=

15

1

−

−20

1

\bf\huge\frac{1}{v} = \frac{1}{15} - \frac{1}{20}

v

1

=

15

1

−

20

1

\bf\huge\frac{1}{v} = \frac{7}{60}

v

1

=

60

7

\bf\huge\texttt v = 8.57 cmv=8.57cm