An object is placed at a distance of 2f infront of a concave mirror of focal length f the magnification produced is
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U=-2f
V=?
1/u+1/v=1/f
1/-2f + 1/v = 1 /f
1/v= 1/f + 1/2f
V = 2f/3
Now, m=-v/u
=-2f/3*-2f
=1/3
Answered by
1
=-2f
V=?
1/u+1/v=1/f
1/-2f + 1/v = 1 /f
1/v= 1/f + 1/2f
V = 2f/3
Now, m=-v/u
=-2f/3*-2f
=1/3
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