Question

an object is placed at a distance of 3 cm from a concave lens of focal length 12cm . find the position nature of the image formed​

Answer 1

Explanation:

use the sign convention properly and then try to solve the questions and also remember the properties and position of the image formed.

Answer 2

The image is formed at the same side of the mirror at the distance of 2.4 cm.

Explanation:

It is given that,

Object distance from the lens, u = -3 cm

Focal length of the concave lens, f = -12 cm

Let v is the image distance from the lens. Using the mirror's formula to find it,

$\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}$

$\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}$

$\dfrac{1}{v}=\dfrac{1}{-12}+\dfrac{1}{-3}$    

v = -2.4 cm

So, the image is formed at the same side of the mirror at the distance of 2.4 cm. The formed image is virtual,erect and magnified.

Learn more,

Lens formula

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