an object is placed at a distance of 30 cm from a concave lens produces an image at 60cm from the lens claculate the focal length
Answers
Answered by
0
Step-by-step explanation:
This is the correct answer for your question
Attachments:
Answered by
2
Step-by-step explanation:
concave lens produces a virtual, erect diminished image.
Using Real Is Positive RIP Convention, u=30 and f=-15
1/u+1/v=1/f
1/30+1/v=−1/15
1/v=−1/15−1/30=−3/30=−1/10
v=−10M=v/u=−1/3
So image is erect, virtual, 1/3 size of object, and 10 cm from the lens, (between lens and object)
Similar questions