Question

an object is placed at a distance of 30 cm from a convex lens of height 4cm and focal length 10cm. find nature size position and magnification

Answer 1

Answer:

v=15cm

Size of img= -2cm

m= -0.5

Nature of img: Real & Inverted

Step-by-step explanation:

u= -30cm

h= 4cm

f=10cm

v=?

nature=?

m=?

size of image=?

1/f=1/v-1/u

1/v=1/f+1/u

1/v=1/10-1/30

1/v=3/30-1/30      (LCM=30)

1/v=2/30

1/v=1/15

v=15

Hence v=15.

m=Size of Image/Size of object=v/u

=S of img/4=15/-30

S of img=-15/30*4

S of img=-1/2*4= -2cm

Hence the Size of the Image is -2cm.

m= v/u=15/-30

  =-1/2= -0.5

Hence the magnification is -0.5

And since m is (-), The nature of the image is Real & Inverted.