Question

an object is placed at a distance of 30 cm from a convex lens of focal length 20 cm . find the position of image

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need quilty ans​

Answer 1

Answer:

$\huge\purple{Given :}$

• Object is placed at a distance of 30 cm from a convex lens.
• Focal length of the lens is 20 cm .

$\huge\purple{To\:Find :}$

• Position of Image .

$\huge\purple{Solution :}$

$\large\green{⟹}$object distance (u) = -30cm

$\large\green{⟹}$Focal Length (f) = 20cm

$\huge\purple{Using\:Formula:}$

$\large\red{⟹}$mirror formula$\frac{1}{f}=\frac{1}{v} -\frac{1}{u}$

$\huge\purple{Putting\:Values:}$

$\huge\blue{⟹}$$\huge\frac{1}{f} + \frac{1}{u} = \frac{1}{v}$

$\huge\blue{⟹}$$\huge\frac{1}{20} + \frac{1}{( - 30)} = \frac{1}{v}$

$\huge\blue{⟹}$$\huge\frac{1}{20} - \frac{1}{30} = \frac{1}{v}$

$\huge\blue{⟹}$$\huge\frac{3 - 2}{60} = \frac{1}{v}$

$\huge\blue{⟹}$$\huge\frac{1}{60} = \frac{1}{v}$

$\huge\sf\fbox\pink{60 cm = v}$

So, the position of the image is 60 cm and the image formed is real and inverted.

Answer 2

Answer:

In order to obtain image coincident with object, the image of object after refraction from the convex lens must be formed on the center of curvature of the convex mirror.

Distance of image from convex lens after refraction from it can be found by using lens equation:

⇒v1=u1+f1=−301+201

⇒v=60cm

Thus, image is formed at a distance of 60cm from the lens.

Thus, the convex mirror should be kept at distance 60cm−10cm=50cm from the lens such that the image is formed at its center of curvature.

$\underline\pink{▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬}$

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