An object is placed at a distance of 30cm from a concave lens of focal length 15cm. Find position and nature of image
Answers
Explanation:
List four characteristics (nature, position, etc.) ... object is placed at a distance of 30 cm from a concave lens of focal length ... Find the position and so it forms an image at 15 cm from the lens ?
As We know that Object is placed at a distance of 30 cm from the Concave lens of Focal length of 15 cm.
- Object (u) = –30 cm
- Focal length (f) = –15 cm
Let the Position of the Image be v.
By using the lens formula, we can calculate the image position by 1/v – 1/u = 1/f.
→ 1/v – 1/u = 1/f
→ 1/v + 1/30 = 1/-15
→ 1/v = 1/–15 - 1/30
→ 1/v = –2–1/30
→ 1/v = –3/30
→ 1/v = –1/10
→ v = –10 cm
Hence,
The Position of the image will be 10 cm to the left side of lens (at the side of object).
Nature of Image: This Formed image will be Virtual & Erect as well as smaller in size (with respect to the Object).
