Question

an object is placed at a distance of 30cm from the pole of a concave lens of focal length 15cm find the position of the image.what is its magnification.​
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Answer 1

Answer:

ham itne hoshiyr nahi par dil dar jaru he

Answer 2

Explanation:

Use lens formula.

1/v - 1/u = 1/f

So, 1/v=1/f+1/u

or,1/v=1/-15+1/-30

or,1/v=-45/450

or,v= -10 cm

Magnification=v/u=-10/-30=1/3

Here,f has to be taken negative because by sign convention, focal length of the concave lens is negative.

Object distance (u) is negative for every case( for any lens or mirror).

Thank you.