An object is placed at a distance of 30cm infront of a concave mirror whose focal length is 15cm then the image distance is
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Answered by
8
Given ;
u = -30 cm
f = -15 cm
v = ?
Using mirror formula ;
(1/f) = (1/v) + (1/u)
(1/-15) = (1/v) + (1/-30)
1/v = (1/30) - (1/15)
1/v = (1-2)/30
v = -30 cm
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The image of formed at a distance of 30 cm in front of the concave mirror.
_____________________
u = -30 cm
f = -15 cm
v = ?
Using mirror formula ;
(1/f) = (1/v) + (1/u)
(1/-15) = (1/v) + (1/-30)
1/v = (1/30) - (1/15)
1/v = (1-2)/30
v = -30 cm
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The image of formed at a distance of 30 cm in front of the concave mirror.
_____________________
Answered by
4
Given,
Object distance, u = - 30cm
Focal length, f = - 15cm
Let's think the image distance is V
Now,
According to mirror formula,
1/f = 1/v + 1/u
or,1/- 15 = 1/v - 1/30
or, (-1/v) = (-1/30) + 1/15
or, 1/v = 1/30 - 1/15
or, 1/v = 1-2/30
or, 1/v = - 1/30
or,v = -30
So the object distance is -30cm in front of the mirror.
Hope it helps.
Object distance, u = - 30cm
Focal length, f = - 15cm
Let's think the image distance is V
Now,
According to mirror formula,
1/f = 1/v + 1/u
or,1/- 15 = 1/v - 1/30
or, (-1/v) = (-1/30) + 1/15
or, 1/v = 1/30 - 1/15
or, 1/v = 1-2/30
or, 1/v = - 1/30
or,v = -30
So the object distance is -30cm in front of the mirror.
Hope it helps.
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