Science, asked by Mehul2275, 10 months ago

An object is placed at a distance of 4 cm from a concave lens of focal length 12 cm. Find the position and

nature of the image.

Answers

Answered by vish143690

Answer:

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u = -4 cm

f = -12 cm

Lens formula : 1/v – 1/u = 1/f

1/v – 1/-4 = 1/-12

1/v = - (1/12 ) – 1/4

1/v = -4/12

V = - 3cm

Image is formed 3 cm infront of the concave lens.

Image is virtual and erect

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Answered by aloksingh17801980

Answer:

Answer:

\Huge\fbox{\color{red}{Hello:-}}

Hello:-

u = -4 cm

f = -12 cm

Lens formula : 1/v – 1/u = 1/f

1/v – 1/-4 = 1/-12

1/v = - (1/12 ) – 1/4

1/v = -4/12

V = - 3cm

Image is formed 3 cm infront of the concave lens.

Image is virtual and erect

< body bgcolor=pink > < marquee \ \textless \ br /\ \textgreater \ direction="right" > < font color=red ><bodybgcolor=pink><marquee \textless br/ \textgreater direction="right"><fontcolor=red>

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An object is placed at a distance of 4 cm from a concave lens of focal length 12 cm. Find the position andnature of the image.​

Answers

V = - 3cm

Image is formed 3 cm infront of the concave lens.

Image is virtual and erect

An object is placed at a distance of 4 cm from a concave lens of focal length 12 cm. Find the position and

nature of the image.