Question

An object is placed at a distance of 4 cm from a concave mirror of focal length 15 cm. find the position and nature of image?​

Answer 1

the position of the image is 1.33 cm, it is a real and inverted image

Full explanation

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Using the Real Is Positive convention, everything is real — therefore positive.

1/u + 1/v = 1/f

1/4 + 1/v = 1/1

1/v = 3/4

v = 4/3 — positive hence real

M = v/u = +1/3 — positive hence inverted

Image is Real, Inverted, Diminished x 1/3, and 4/3 cm from mirror.

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Answer 2

✰ Question Given :

• An object is placed at a distance of 4cm from a Concave mirror of focal length 15 cm. Find the position and nature of the image.

✰ Required Solution :

★ Value Given to us :

• object is placed at a distance of 4 cm

• Concave mirror of focal length 15 cm.

★ Formula Used Here :

• 1/v + 1/u = 1/f

★ Putting Value in Formula :

• ➦ 1/v + 1/(- 15) = 1/4

• ➦ 1/v - 1/15 = 1/4

• ➦ 1/v = 1/4 + 1/15

• ➦ 1/v = (15 + 4)/60

• ➦ 1/v = 19/60

• ➦ 1/v = 60 / 19

• ➦ v = 3.15cm

★ Hence :

• The image distance is 3 (Approx) cm.

✰ Nature , Position of the image :

• The image is formed behind the mirror and it is virtual and erect.

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