Question

an object is placed at a distance of 40 cm from a convex mirror of radius of curvature 30 cm.what is the image distance​

Answer 1

Solution :

$v = \frac{40}{3}$

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Answer 2

• Object distance, u = -40 cm
• Radius of curvature, R = 30 cm

We know,

◙ Focal length = R/2

⇒f = 30/2

⇒f = 15 cm

We also know,

◙ Mirror formula :- 1/v + 1/u = 1/f

Putting the values :-

1/v + 1/(-40) = 1/15

⇒1/v = 1/15 + 1/40

⇒1/v = (8 + 3)/120

⇒1/v = 11/120

⇒v = 120/11

⇒v = 10.90 cm

∴ The image distance is 10.9 cm.