An object is placed at a distance of 40 cm infront of a convex lens of focal length 20 cm the image is formed at which distance
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Answered by
1
Object-distance = u = -40 cm
Focal-length = f = +20 cm
Image-distance = v = ?
By lens formula ,
1/v - 1/u = 1/f
i.e., 1/v = 1/f + 1/u
= 1/+20 + 1/(-40)
= 1/20 - 1/40
= 20/800
= 1/+40
Thus , v = +40
i.e., the image is formed 40 cm on the other side of the lens .
:)
Focal-length = f = +20 cm
Image-distance = v = ?
By lens formula ,
1/v - 1/u = 1/f
i.e., 1/v = 1/f + 1/u
= 1/+20 + 1/(-40)
= 1/20 - 1/40
= 20/800
= 1/+40
Thus , v = +40
i.e., the image is formed 40 cm on the other side of the lens .
:)
Answered by
0
Answer:
hiii
Explanation:
object distance , u = - 40 cm
focal length , f = 20 cm
size of object , b1 = 8 cm
we know that
1/ f = 1 / v - 1/ u
1/ 20 = 1/ v - 1/-40
1/v = 1/20 - 1/40
v = 40 cm
thus image distance , v = 40 cm
b2 / b1 = v/ u
b2 = 40 /-40× b1
40/-40×8
=-8 cm
this is your ans. I hope it helps you
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