Question

an object is placed at a distance of 45 cm in front of a convex lens of focal length 30 cm between f and 2f then position of the image will be​

Answer 1

Given:

• Distance of object (u) = -45 cm
• Focal length of LENS (f) = 30 cm

To find:

• Position of image = ?

Formula used:

$\\\\ \bigstar \: { \underline{\boxed{ \bf {\color{lime}{\frac{1}{v} - \frac{1}{u} = \frac{1}{f} }}}}}$

Solution:

★Substituting the values in the lens formula we get,

$\\ \sf \dashrightarrow\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$

$\sf \dashrightarrow\frac{1}{v} = \frac{1}{30} - \frac{1}{45}$

$\sf \dashrightarrow\frac{1}{v} = \frac{3 - 2}{90}$

$\sf \dashrightarrow\frac{1}{v} = \frac{1}{90}$

$\sf \dashrightarrow \: v = 90$

${\bigstar{\red{\underline{\boxed{\sf{v = 90 \: cm}}}}}}$

hence, Position of the image ( V ) = 90 cm

Answer 2

Answer:

V=90

Step-by-step explanation:

Given:

• Distance of object (u) =-45
• Focal length of LENS(f) =30

To find:

• Position of image=?

Formula used:

1/v - 1/u = 1/f

Solution:

Substituting the values in the lens formula we get,

--> 1/v - 1/u = 1/f

--> 1/v = 1/30 - 1/45

--> 1/v = 3-2/90

--> 1/v = 1/90

--> v = 90

hence, position of the image (v) = 90 cm

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