Question

an object is placed at a distance of 50 cm from a concave lens of focal length 30 cm find the nature and the position of the image​

Answer 1

Answer:

Explanation:hope it helps you

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Answer 2

Answer:

Answer

u = -50cm, f = -30cm, v = ?

1/f = 1/v-1/u

-1/30 = 1/v+1/50

1/v = -1/30-1/50

1/v = -5-3/150

So v = -150/8 or -18.75

Explanation:Image will be on the left side of the lens. Also as it is a concave lens, image will be virtual and erect.

I hope this helps!!!!