Question

an object is placed at a distance of 50 cm from a concave lens of focal length 20cm for the nature and position of the image also find the magnification of the image​

Answer 1

Answer:

1/v + 1/u = 1/f

u = 50 cm , f = 20 cm

Putting the value in formula we get ,

1/v = 1/ f - 1/u

1/v = 1/0.2 - 1/ (-0.5)

1/v = 1/0.2+1/0.5

v = 0.1428

m = -v /u = 0.2856

Nature = Virtual , image form behind the mirror

Explanation

Hope this helps :)