Question

an object is placed at a distance of 50 cm from a concave lens of focal length 30 cm find the nature and the position of the image

Answer 1

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Answer 2

Answer:

Nature of the image is is virtual and position of the image is erect

Explanation:

The focal length of a concave lens is always negative in accordance with the sign convention.

Concave lens:

• An image that is diminished, upright, and virtual is produced by a concave lens, which diverges a straight light beam from the source.
• It is capable of producing both actual and virtual images. Concave lenses have at least one curved interior surface.
• Light diverges on a diverging lens, which is a concave lens that is rounded in the middle and bulges outward through the corners.

The focal length of the concave lens is negative.

f = - 30 cm

u = - 50 cm

we know that,

$\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$

⇒ $\frac{1}{-30} = \frac{1}{v} - \frac{1}{-50}$

⇒ $\frac{1}{-30} + \frac{1}{-50} = \frac{1}{v}$

⇒  $\frac{-50 -30}{100} = \frac{1}{v}$

⇒ $\frac{-80}{1000} = \frac{1}{v}$

⇒ $\frac{-8}{100} = \frac{1}{v}$

⇒ v = -  $\frac{100}{8}$

⇒ v = - 12.5 cm

Focal length of concave lens is virtual and erect

Final answer:

Nature of the image is is virtual and position of the image is erect

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