An object is placed at a distance of 50 cm in front of a concave mirror of focal length 25 cm .Find the image distance .If the object is 10 cm high what will be the nature and size of the image?
Answers
Answered by
6
Answer:u= -50cm
f=-25cm
v=?
Now put mirror formula, i. e
1/f=1/u+1/v
1/v=1/25-1/50=1/50
m=-v/u
=-1/50/-1/50=1
m=hi/ho=hi/10=1
hi=10cm
Explanation:
Answered by
10
Answer:
Explanation:
Distance from mirror, u = -50cm
Focal Length, f = -25cm (concave mirror)
Height of object, h₁ = 10cm
TO find: v and height of image(h₂)
Using the mirror formula,
⇒ 1/u + 1/v = 1/f
⇒ 1/-50 + 1/v = 1/-25
⇒ 1/v = -1/25 + 1/50
⇒ 1/v = -2 + 1 / 50
⇒ 1/v = -1/50
⇒ v = -50 cm
The negative sign indicates that the image obtained is REAL AND INVERTED.
BY maginfication formula,
m = h₂/h₁ = -v/u
⇒ h₂/h₁ = -v/u
⇒ h₂/10 = -(-50)/-50
⇒ h₂ = -1 × 10
⇒ h₂ = -10cm
Ans. Size of the image is -10cm.
Here is your answer
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