Question

An object is placed at a distance of 50 cm in front of a convex mirror of focal
length 25 cm. Find the image distance. What will be its nature ?​

Answer 1

Answer:

IMAGE DISTANCE=+16.6 CM

NATURE=VIRTUAL AND ERECT.

Explanation:

In convex mirror

Object distance = - 50cm

Focal length = + 25cm

Image distance=?

Nature of image?

Apply mirror formula,

⇒1/v+1/u=1/f

⇒1/v+(-1/50)=1/25

⇒1/v=1/50+1/25

∴1/v=3/50

∴v=+16.6 cm

Hence, image distance is + 16.6 cm

Nature of image= Virtual and erect

HOPE IT HELPS AND IF YOU LIKE IT MARK IT AS BRAINLIEST.

Answer 2

Answer:

1\f=1\u+1\v

1\25= -1\50 + 1\v

2+1\50= 1\v

V=50\3