An object is placed at a distance of 50cms from conves lens of focal length 20cm.find the nature and position of the image.
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Answered by
6
u = - 50 cm
f = 20 cm
1/v - 1/u= 1/f
1/v + 1/50 = 1/20
1/v = 1/20 - 1/50
1/v = 3/100
v = + 100/3
v = + 33.33
The image is on the right side of the lens and is real and inverted.
f = 20 cm
1/v - 1/u= 1/f
1/v + 1/50 = 1/20
1/v = 1/20 - 1/50
1/v = 3/100
v = + 100/3
v = + 33.33
The image is on the right side of the lens and is real and inverted.
amrita5678:
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Answered by
2
u = - 50 cm
f = 20 cm
1/v - 1/u= 1/f
1/v + 1/50 = 1/20
1/v = 1/20 - 1/50
1/v = 3/100
v = + 100/3
v = + 33.33
The image is on the right side of the lens(because "v" is positive) and is real and inverted.
f = 20 cm
1/v - 1/u= 1/f
1/v + 1/50 = 1/20
1/v = 1/20 - 1/50
1/v = 3/100
v = + 100/3
v = + 33.33
The image is on the right side of the lens(because "v" is positive) and is real and inverted.
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