Question

An object is placed at a distance of 5cm in front of a concave mirror of focal length 2 cm. Find the position, size magnification and nature of the image so formed​

Answer 1

Answer: 1 cm

Explanation:  Given,

Size of object  h  

o

​  

=5cm

Size of the image  h  

i

​  

=?

Focal length,  f=−10cm

Object distance  u=−60cm

Image distance  v=?

Using mirror formula,  

f

1

​  

=  

v

1

​  

+  

u

1

​  

 

−10

1

​  

=  

v

1

​  

+  

−60

1

​  

 

v

1

​  

=  

60

−6+1

​  

 

v=−12cm

Hence, the position of the object is at 12 cm in front of the mirror.

Magnification (M)=  

h  

o

​  

 

h  

i

​  

 

​  

=  

u

−v

​  

=  

−60

12

​  

=−0.2

h  

i

​  

=−0.2×h  

o

​  

 

h  

i

​  

=−0.2×5=−1cm

Height of inverted image is 1cm.

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