An object is placed at a distance of 60cm from a convex lens of focal length 30cm. If height of object is 4cm, then calculate the position and nature of image. Also draw a ray diagram of above situation.
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In this question I am going to use a scale of 1:5 to draw this diagram.
When I use this scale:
Focal length =20/5=4cm
Object height =4/5=0.8cm
The object distance =30/5 =6cm.
From the diagram, the image height is 1.6cm.
Which from the scale is : 1.6 × 5=8cm
The ratio of image size to object size is : 8:4=2:1
The ratio= 2:1
Find diagram in the image.
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