Question

An object is placed at a distance of 60cm from a diverging lens of focal length 20cm. Find the position and nature of the image?

Answer 1

Object distance u = -50 cm
Focal length of concave lens f = -20 cm
Lens formula: 1/v - 1/u = 1/f
1/v = 1/f + 1/u
= 1/(-20) + 1/(-50)
= -7/100

image distance v = -100/7 = - 14.3 cm

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Answer 2

A diverging lens is also called a concave lens.

The focal length of a concave lens is negative.

For instance in this case the focal length is -20 cm.

We can get the image distance using the lens formula.

The lens formula is given below:

1/f = 1/v + 1/u

Where :

u = the object distance.

v = the image distance

f = the focal length

In this case :

f = -20

u = 60 cm

Doing the substitution we have:

1/-20 - 1/60 = 1/v

= -1/15

v = - 15 cm

The image distance is therefore 15 cm  when we ignore the negative sign.

The negative sign indicates that the image is virtual.