an object is placed at a distance of 8cm from a concave mirror of focal length 10cm find the nature of the image
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Answered by
38
object distance u= 8 cm
focal length f = 10 cm
image distance v= ?
mirror formula 1/u+1/v=1/f
1/v=(1/f)-(1/u)
= 1/10–1/8
= (4–5)/40
1/v=-1/40
v=-40 cm
-ve sign indicates the image is formed on the other side of the mirror, virtual and erect.
focal length f = 10 cm
image distance v= ?
mirror formula 1/u+1/v=1/f
1/v=(1/f)-(1/u)
= 1/10–1/8
= (4–5)/40
1/v=-1/40
v=-40 cm
-ve sign indicates the image is formed on the other side of the mirror, virtual and erect.
Answered by
19
The image formed is virtual, erect and magnified.
- Given,
u = 8 cm, f = 10 cm
f > u
- The object is placed between focus and pole of the mirror.
- In this case, the image is formed behind the mirror.
- The image formed would be virtual, erect and enlarged.
Ray diagram:
- Ray from A parallel to principal axis, passes through focus after reflection.
- Ray from A passing through center of curvature is undeviated after reflection.
- When these two rays are extended backwards, they meet at point A'.
- A'B' is the image of object AB which is virtual, erect and magnified.
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