Question

an object is placed at a distance of f/2 from a convex mirror, then the image is formed at a) 3f/2 b) 2f, virtual and erect c) 2f, real and Inverted d) the focus F virtual and erect​

Answer 1

$\huge\star\underline\mathfrak\red{Answer:-}$

Using Lens Formula , (1/f)=(1/v)−(1/u)

put f=f , u=−f/2

we get v=−f

As v is negative , the image is in the same side as of object so image is virtual because we have used a convex lens.

magnification m=(−v/u)=−2 so the image will be double of the object in the size.

Answer 2

Answer:

⋆

Answer:−

Using Lens Formula , (1/f)=(1/v)−(1/u)

put f=f , u=−f/2

we get v=−f

As v is negative , the image is in the same side as of object so image is virtual because we have used a convex lens.

magnification m=(−v/u)=−2 so the image will be double of the object in the size.